2x^2+8x=1/3

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Solution for 2x^2+8x=1/3 equation: 


x in (-oo:+oo)

2*x^2+8*x = 1/3 // - 1/3

2*x^2+8*x-(1/3) = 0

2*x^2+8*x-1/3 = 0

2*x^2+8*x-1/3 = 0

DELTA = 8^2-(-1/3*2*4)

DELTA = 200/3

DELTA > 0

x = ((200/3)^(1/2)-8)/(2*2) or x = (-(200/3)^(1/2)-8)/(2*2)

x = ((200/3)^(1/2)-8)/4 or x = (-((200/3)^(1/2)+8))/4

x in { (-((200/3)^(1/2)+8))/4, ((200/3)^(1/2)-8)/4 }

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